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Sender:
College Hockey discussion list <[log in to unmask]>
Subject:
From:
"Ralph N. Baer" <[log in to unmask]>
Date:
Wed, 9 Nov 1994 06:31:09 -0500
Reply-To:
"Ralph N. Baer" <[log in to unmask]>
Parts/Attachments:
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Glen wrote:
 
>   1993-94 Regular Season Conference Games
> Conference  Games  Overtimes    Ties   Ties/OT
>               #      #    %    #    %     %
> CCHA         166    27  16.3  13   7.8  48.1
> WCHA         158    22  13.9  14   8.9  63.6
> ECAC         132    32  24.2  18  13.6  56.3
> HE            96    18  18.6  13  13.6  72.2
> --------------------------------------------
> Total        552    99  17.9  58  10.5  58.6
 
 
So let us assume that 1993-94 was a normal year and 10.5% of all games
are tied after 65 minutes.  To date, there have been 12 games in HE of
which 4 have been tied after 65 minutes.  The question is what is the
chance that 4 games out of 12 would be tied if the chance of a
tie is 0.105?
 
The answer is 12!/(4!*8!) * (.895)**8 * (.105)**4 = .0248
If one adds to this the chance that there were more than four ties
(certainly if people were amazed that there were four ties, they would
be at least as amazed if there were five or more) the result is .0301.
 
Although a 3% chance is not too likely, events which such probability
happen often enough.  [About 3% of the time :-).]  I suspect that in a
couple of weeks the ratio will start approaching .105.
 
Ralph Baer     RPI '68, '70, '74

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