*Message:
From: SCERO at OLEC
Date: 10/18/94 3:43PM
To: INTERNET:[log in to unmask] at OCF_INFORM
Subject: Re[2]: BG-MSU penalty situation
Contents:
 
> On Mon, 17 Oct 1994, G. M. Finniss wrote:
> 1)  How does one score a 5-on-3c situation as regards to number of power
>     plays?  Let's give a scenario:  Team A is penalized for a 2-minute minor
>     at 10:00 of a period.  They get a second minor at 10:30.  Team B doesn't
>     score on either the first 5-on-4 (from 10:00 to 10:30), the 5-on-3 (10:30
>     to 12:00) or the second 5-on-4 (12:00 to 12:30).  Technically, how many
>     power plays did Team B have?
 
> Tony Frolik writes...
> I always thought it was 3 power plays.  one 5 on 4 to start, one 5 on 3
> in the middle, and another 5 on 4 to finish.
 
It's a very simple method to calculating the number of power plays a given team
has in any give situation.  How many penalties were given to team A which causes
it to be below the numerical strength of it's opponents?  In the above example,
the answer would be 2.  Regardless of whether or not a goal is scored, the
number of power play "opportunities" can never be greater than the number of
penalties given.  This includes the situation where team A is given 2 penalties
at the same stoppage of play.  For example: Player A gets 2:00 at 10:00 and
Player B gets 2:00 at 10:00.  How many power play opportunities? Ans: 2. Why...
There were two penalties accessed to team A which each caused them to have an
on-ice numerical disadvantage to their opponents.  What if no goal is scored?
Doesn't matter, the "opportunity" to score two power play goals was always
there.
 
Rick
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